q^2+16q-17=0

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Solution for q^2+16q-17=0 equation:


Simplifying
q2 + 16q + -17 = 0

Reorder the terms:
-17 + 16q + q2 = 0

Solving
-17 + 16q + q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-17 + -1q)(1 + -1q) = 0

Subproblem 1

Set the factor '(-17 + -1q)' equal to zero and attempt to solve: Simplifying -17 + -1q = 0 Solving -17 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '17' to each side of the equation. -17 + 17 + -1q = 0 + 17 Combine like terms: -17 + 17 = 0 0 + -1q = 0 + 17 -1q = 0 + 17 Combine like terms: 0 + 17 = 17 -1q = 17 Divide each side by '-1'. q = -17 Simplifying q = -17

Subproblem 2

Set the factor '(1 + -1q)' equal to zero and attempt to solve: Simplifying 1 + -1q = 0 Solving 1 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1q = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1q = 0 + -1 -1q = 0 + -1 Combine like terms: 0 + -1 = -1 -1q = -1 Divide each side by '-1'. q = 1 Simplifying q = 1

Solution

q = {-17, 1}

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